If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(20x^2)-x-30=0
We add all the numbers together, and all the variables
20x^2-1x-30=0
a = 20; b = -1; c = -30;
Δ = b2-4ac
Δ = -12-4·20·(-30)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-49}{2*20}=\frac{-48}{40} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+49}{2*20}=\frac{50}{40} =1+1/4 $
| 150/55=h | | 3z+3;z=8 | | (-3x^)=-6x | | .4x+108=180 | | 3x2-8x=3 | | 6(3+v)=36 | | x+60+x+51+80=180 | | 20r+5r+3r−22r=12 | | -11/18z=1/3 | | 3(4-2x)=4-(6x-) | | 2(w+6)=22 | | 55-5x=90+10x | | 45=9(s-1) | | 3.66+8.1h=7.5h | | 1.6q-5.9-4.8q=-2.2q-5.9 | | x+5/5+x+4/3=2 | | 45=9(s-1 | | 100/62.5=h/8.3 | | 6*3=(x*5)–(x*2) | | 3(5+p)=15 | | 4x/9+2x/3=10 | | -3(4/7x)=0 | | -3/4s-2/5=7/10 | | 1/3h-4(2/3h-3)=60 | | 6(t-8)=6 | | (20x^2)-×-30=0 | | B+8)(3b-1)=0 | | -3x+8-4(x-1)=-2x+6-4x+4 | | 11x-40=65+14x | | 3(7-2x=14-8(x-1) | | 11x-40=65=14x | | 63=7(5+b) |